(a-b-c)^2: BONGDATV

(a+b+c)^2+(a-b-c)^2 Using the identity (a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ac: =[a^2+b^2+c^2+2ab+2bc+2ac][a^2+(-b)^2+(-c)^2+2a(-b)+2(-b)(-c)+2a(-c)] =a^2+b^2+c^2+2ab+2bc+2ac+a^2+b^2+c^2-2ab+2bc-2ac =2a^2+2b^2+2c^2+4bc =2[a^2+b^2+c^2+2bc] therefore (a+b+c)^2+(a-b-c)^2=2[a^2+b^2+c^2+2bc]

Chapter 1 Class 10 Real Numbers. Concept wise. Introduction. Algebra Formulas. Last updated at April 16, 2024 by Teachoo. Square Formulas. (a + b) 2 = a 2 + b 2 + 2ab. (a − b) 2 = a 2 + b 2 − 2ab. a 2 − b 2 = (a − b) (a + b) (x + a) (x + b) = x 2 + (a + b) x + ab. (a + b + c) 2 = a 2 + b 2 + c 2 + 2ab + 2bc + 2ca.

Verify my answer. How to improve your answer: Learn how to solve special products problems step by step online. Expand the expression (a-b-c)^2. Expand the trinomial using the formula \left (a+b+c\right)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc. Multiply 2 times -1. Multiply 2 times -1.

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